8.Mechanical Properties of Solids
medium

$20\,m$ લંબાઈના અને $2\,cm$ ખેંચાણ ધરાવતા એક સ્ટીલના તારમાં સંગ્રહિત સ્થિતિસ્થાપક સ્થિતિઊર્જા $80\,J$ છે. તારના આડછેદનું ક્ષેત્રફળ ........ $mm ^2$ થશે. $\left( y =2.0 \times 10^{11}\,Nm ^{-2}\right.$ છે.)

A

$38$

B

$36$

C

$40$

D

$34$

(JEE MAIN-2023)

Solution

Energy per unit volume $=\frac{1}{2} \text { stress } \times \text { strain }$

Energy $=\frac{1}{2} \text { stress } \times \text { strain } \times \text { volume }$

$80=\frac{1}{2} \times Y \times \text { strain }^2 A \times \ell$

$80=\frac{1}{2} \times 2 \times 10^{11} \times \frac{\left(2 \times 10^{-2}\right)^2}{400} \times A \times 20$

$20=\frac{10^{+\prime}}{20} \times A$

$40 \times 10^{-6} m ^2=A$

$A=40\,mm ^2$

Standard 11
Physics

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