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1. Electric Charges and Fields
easy
The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass and charge of an electron respectively are $9.1 \times 10^{-31}\,kg$ and $1.6 \times$ $10^{-19}\,C$.)
A
$-5.6 \times 10^{-11} N / C$
B
$-4.8 \times 10^{-15} N / C$
C
$-1.6 \times 10^{-19} N / C$
D
$-3.2 \times 10^{-19} N / C$
Solution
(a)
$- eE = mg$
$\overrightarrow{ E } =-\frac{9.1 \times 10^{-31} \times 10}{1.6 \times 10^{-19}}=-5.6 \times 10^{-11} N / C$
Standard 12
Physics
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