The distance between a proton and electron both having a charge $1.6 \times {10^{ - 19}}\,coulomb$, of a hydrogen atom is ${10^{ - 10}}\,metre$. The value of intensity of electric field produced on electron due to proton will be
The distance between a proton and electron both having a charge $1.6 \times {10^{ - 19}}\,coulomb$, of a hydrogen atom is ${10^{ - 10}}\,metre$. The value of intensity of electric field produced on electron due to proton will be
- A
$2.304 \times {10^{ - 10}}\,N/C$
- B
$14.4\,V/m$
- C
$16\,V/m$
- D
$1.44 \times {10^{11}}\,N/C$
Similar Questions
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Two charges each equal to $\eta q({\eta ^{ - 1}} < \sqrt 3 )$ are placed at the corners of an equilateral triangle of side $a$. The electric field at the third corner is ${E_3}$ where $({E_0} = q/4\pi {\varepsilon _0}{a^2})$
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- [AIEEE 2004]
Explain electric field and also electric field by point charge.
Explain electric field and also electric field by point charge.
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