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8.Electromagnetic waves
hard
The electric field of an electromagnetic wave in free space is represented as $\vec{E}=E_0 \cos (\omega t-k z) \hat{i}$.The corresponding magnetic induction vector will be :
A
$\vec{B}=E_0 C \cos (\omega t-k z) \hat{j}$
B
$\vec{B}=\frac{E_0}{C} \cos (\omega t-k z) \hat{j}$
C
$\vec{B}=E_0 \operatorname{Cos}(\omega t+k z) \hat{j}$
D
$\vec{B}=\frac{E_0}{C} \cos (\omega t+k z) \hat{j}$
(JEE MAIN-2024)
Solution
Given $\vec{E}=E_0 \cos (\omega t-k z) \hat{i}$
$ \vec{B}=\frac{E_0}{C} \cos (\omega t-k z) \hat{j} $
$ \hat{C}=\hat{E} \times \hat{B}$
Standard 12
Physics