8.Electromagnetic waves
hard

The electric field of an electromagnetic wave in free space is represented as $\vec{E}=E_0 \cos (\omega t-k z) \hat{i}$.The corresponding magnetic induction vector will be :

A

 $\vec{B}=E_0 C \cos (\omega t-k z) \hat{j}$

B

 $\vec{B}=\frac{E_0}{C} \cos (\omega t-k z) \hat{j}$

C

 $\vec{B}=E_0 \operatorname{Cos}(\omega t+k z) \hat{j}$

D

 $\vec{B}=\frac{E_0}{C} \cos (\omega t+k z) \hat{j}$

(JEE MAIN-2024)

Solution

Given $\vec{E}=E_0 \cos (\omega t-k z) \hat{i}$

$ \vec{B}=\frac{E_0}{C} \cos (\omega t-k z) \hat{j} $

$ \hat{C}=\hat{E} \times \hat{B}$

Standard 12
Physics

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