- Home
- Standard 12
- Physics
2. Electric Potential and Capacitance
hard
The electric potential at the surface of an atomic nucleus $(z=50)$ of radius $9 \times 10^{-13} \mathrm{~cm}$ is ________$\times 10^6 \mathrm{~V}$.
A
$10$
B
$9$
C
$7$
D
$8$
(JEE MAIN-2024)
Solution
$ \text { Potential }=\frac{k Q}{R}=\frac{k \cdot Z e}{R} $
$ =\frac{9 \times 10^9 \times 50 \times 1.6 \times 10^{-19}}{9 \times 10^{-13} \times 10^{-2}} $
$ =8 \times 10^6 \mathrm{~V}$
Standard 12
Physics
Similar Questions
medium