End A of a rod AB of length 1,m is maintained at 80,^oC and end B at 0,^oC. temperature at a distanc

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10-2.Transmission of Heat

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The end $A$ of a rod $AB$ of length $1\,m$ is maintained at $80\,^oC$ and the end $B$ at $0\,^oC.$ The temperature at a distance of $60\,\,c.m.$ from the end $A$ is......... $^oC$

A

$16$

B

$32$

C

$48$

D

$64$

Solution

$\left(\frac{\mathrm{dQ}}{\mathrm{dt}}\right)_{\mathrm{AC}}=\left(\frac{\mathrm{dQ}}{\mathrm{dt}}\right)_{\mathrm{AB}}$

$\Rightarrow \frac{\mathrm{KA}}{1}[80-0]=\frac{\mathrm{KA}}{0.6}[80-0]$

$\therefore \theta=32^{\circ} \mathrm{C}$

Standard 11

Physics

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