The energy of a photon is $E = hv$ and the momentum of photon $p = \frac{h}{\lambda }$, then the velocity of photon will be
The energy of a photon is $E = hv$ and the momentum of photon $p = \frac{h}{\lambda }$, then the velocity of photon will be
- A
$E/p$
- B
$Ep$
- C
${\left( {\frac{E}{p}} \right)^2}$
- D
$3 \times {10^8}m/s$
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