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11.Dual Nature of Radiation and matter
easy
The energy of a photon of light of wavelength $450 nm$ is
A
$4.4 \times {10^{ - 19}}J$
B
$2.5 \times {10^{ - 19}}J$
C
$1.25 \times {10^{ - 17}}J$
D
$2.5 \times {10^{ - 17}}J$
Solution
(a) $E = \frac{{hc}}{\lambda } = \frac{{6.62 \times {{10}^{ – 34}} \times 3 \times {{10}^8}}}{{450 \times {{10}^{ – 9}}}}$
$ = 4.4 \times {10^{ – 19}}J$
Standard 12
Physics
