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11.Dual Nature of Radiation and matter
easy
There are ${n_1}$ photons of frequency ${\gamma _1}$ in a beam of light. In an equally energetic beam, there are ${n_2}$ photons of frequency ${\gamma _2}$. Then the correct relation is
A
$\frac{{{n_1}}}{{{n_2}}} = 1$
B
$\frac{{{n_1}}}{{{n_2}}} = \frac{{{\gamma _1}}}{{{\gamma _2}}}$
C
$\frac{{{n_1}}}{{{n_2}}} = \frac{{{\gamma _2}}}{{{\gamma _1}}}$
D
$\frac{{{n_1}}}{{{n_2}}} = \frac{{\gamma _1^2}}{{\gamma _2^2}}$
Solution
(c)$E = nh\nu \Rightarrow \nu \propto \frac{1}{n} \Rightarrow \frac{{{n_1}}}{{{n_2}}} = \frac{{{\gamma _2}}}{{{\gamma _1}}}$.
Standard 12
Physics
