The energy of hydrogen atom in $n^{th}$ orbit is $E_n$, then the energy in $n^{th}$ orbit of singly ionised helium atom will be
$4E_n$
$E_n/4$
$2E_n$
$E_n/2$
$E \propto \frac{{{z^2}}}{{{n^2}}}$
Assertion $(A)$ : The magnetic moment $(\mu)$ of an electron revolving around the nucleus decreases with increasing principle quantum number $(n)$.
Reason $(R)$ : Magnetic moment of the revolving electron, $\mu \propto n$.
According to the Rutherford’s atomic model, the electrons inside the atom are
Show the trajectory of $\alpha -$ particle of different impact parameter and using it how did Rutherford determine the upper limit of the nuclear size ?
In third orbit of hydrogen atom, de Broglie wavelength of electron is $\lambda $ then radius of third orbit is
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