In third orbit of hydrogen atom, de Broglie wavelength of electron is $\lambda $ then radius of third orbit is
In third orbit of hydrogen atom, de Broglie wavelength of electron is $\lambda $ then radius of third orbit is
- A
$3\lambda $
- B
$\lambda $
- C
$\frac{{3\lambda }}{{2 }}$
- D
$\frac{{\lambda }}{{2 }}$
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