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14.Waves and Sound
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The equation of a stationary wave is
$y = 0.8\,\cos \,\,\left( {\frac{{\pi x}}{{20}}} \right)\,\sin \,200\,\pi t$
where $x$ is in $cm$ and $t$ is in $sec$ . The separtion between consecutive nodes will be .... $cm$
A
$20$
B
$10$
C
$40$
D
$30$
Solution
$\frac{2 \pi}{\lambda}=\frac{\pi}{20}$
$\lambda=40 \mathrm{\,cm}$
distance between two consecutive nodes is
$\frac{\lambda}{2}=\frac{40}{2}=20 \mathrm{\,cm}$
Standard 11
Physics
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