Gujarati
Hindi
14.Waves and Sound
normal

The equation of a stationary wave is

$y = 0.8\,\cos \,\,\left( {\frac{{\pi x}}{{20}}} \right)\,\sin \,200\,\pi t$

where $x$ is in $cm$ and $t$ is in $sec$ . The separtion between consecutive nodes will be .... $cm$

A

$20$

B

$10$

C

$40$

D

$30$

Solution

$\frac{2 \pi}{\lambda}=\frac{\pi}{20}$

$\lambda=40 \mathrm{\,cm}$

distance between two consecutive nodes is

$\frac{\lambda}{2}=\frac{40}{2}=20 \mathrm{\,cm}$

Standard 11
Physics

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