The equation of an equipotential line in an e | vedclass

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Question

Electric field is perpendicular to equipotential line

$\because \quad y=2 x$

or $\quad \frac{d y}{d x}=2$

$	herefore \quad \mathrm{m}_{1}=2$

Vedclass · Accepted Answer

$- 8  \hat i + 4  \hat j$

Vedclass · Answer

Electric field is perpendicular to equipotential line

$\because \quad y=2 x$

or $\quad \frac{d y}{d x}=2$

$	herefore \quad \mathrm{m}_{1}=2$

$	herefore \quad \mathrm{m}_{1} \mathrm{m}_{2}=-1$

$\mathrm{m}_{2}=-\frac{1}{2}$

$	herefore$ $	an 	heta=-\frac{1}{2}$

where $	heta$ is angle with $x$ $-axis.$

$	an 	heta=\frac{4}{-8}=-\frac{1}{2}$

The equation of an equipotential line in an electric field is $y = 2x$, then the electric field strength vector at $(1, 2)$ may be

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