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Mathematical Reasoning
medium
The false statement in the following is
A
$p \wedge (\sim p)$ is a contradiction
B
$(p \Rightarrow q) \Leftrightarrow (\sim q \Rightarrow \;\sim p)$ is a contradiction
C
$\sim (\sim p) \Leftrightarrow p$ is a tautology
D
$p \vee (\sim p)$ is a tautology
Solution
(b) $p \Rightarrow q$ is logically equivalent to $\sim q \Rightarrow \;\sim p$
$(p \Rightarrow q) \Leftrightarrow (\sim q \Rightarrow \;\sim p)$ is a tautology but not a contradiction.
Standard 11
Mathematics
