Gujarati
Mathematical Reasoning
medium

The false statement in the following is

A

$p \wedge (\sim p)$ is a contradiction

B

$(p \Rightarrow q) \Leftrightarrow (\sim q \Rightarrow \;\sim p)$ is a contradiction

C

$\sim (\sim p) \Leftrightarrow p$ is a tautology

D

$p \vee (\sim p)$ is a tautology

Solution

(b) $p \Rightarrow q$ is logically equivalent to $\sim q \Rightarrow \;\sim p$

 $(p \Rightarrow q) \Leftrightarrow (\sim q \Rightarrow \;\sim p)$ is a tautology but not a contradiction.

Standard 11
Mathematics

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