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(b) When length of the liquid column remains constant, then the level of liquid moves down with respect to the container, thus $\gamma$ must be less t

Vedclass · Accepted Answer

$\gamma= 2\alpha$

Vedclass · Answer

(b) When length of the liquid column remains constant, then the level of liquid moves down with respect to the container, thus $\gamma$ must be less than $3\alpha$.

Now we can write $V = V_0(1 + \gamma \Delta T)$

Since $V = Al_0 = [A_0 (1 + 2\alpha \Delta T)]l_0 = V_0 (1 + 2\alpha \Delta T)$

Hence $V_0(1 + \gamma \Delta T) = V_0(1 + 2\alpha \Delta T) ==> \gamma= 2\alpha$ .

The figure shows a glass tube (linear co-efficient of expansion is $\alpha$) completely filled with a liquid of volume expansion co-efficient $\gamma$. On heating length of the liquid column does not change. Choose the correct relation between $\gamma$ and $\alpha$

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