The figure shows two parallel equipotential surfaces $A$ and $B$ kept a small distance $r$ apart from each other. $A$ point charge of $q$ coulomb is taken from the surface $A$ to $B$. The amount of net work done will be

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  • A

    $ - \frac{1}{{4\pi {\varepsilon _0}}}\frac{q}{r}$

  • B

    $ \frac{1}{{4\pi {\varepsilon _0}}}\frac{q}{r^2}$

  • C

    $- \frac{1}{{4\pi {\varepsilon _0}}}\frac{q}{r^2}$

  • D

    Zero

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