Figure shows two parallel equipotential surfaces A and B kept a small distance r apart from each oth

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1. Electric Charges and Fields

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The figure shows two parallel equipotential surfaces $A$ and $B$ kept a small distance $r$ apart from each other. $A$ point charge of $q$ coulomb is taken from the surface $A$ to $B$. The amount of net work done will be

$ - \frac{1}{{4\pi {\varepsilon _0}}}\frac{q}{r}$

$ \frac{1}{{4\pi {\varepsilon _0}}}\frac{q}{r^2}$

$- \frac{1}{{4\pi {\varepsilon _0}}}\frac{q}{r^2}$

Zero

Solution

${\rm{W}} = {\rm{q}}\left( {{{\rm{V}}_{\rm{A}}} – {{\rm{V}}_{\rm{B}}}} \right) = {\rm{q}} \times 0 = 0$ ( ${{{\rm{V}}_{\rm{A}}} = {{\rm{V}}_{\rm{B}}}},$ equipotential)

Standard 12

Physics

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The figure shows two parallel equipotential surfaces $A$ and $B$ kept a small distance $r$ apart from each other. $A$ point charge of $q$ coulomb is taken from the surface $A$ to $B$. The amount of net work done will be

Solution

Similar Questions

In the figure a potential of $+ 1200\, V$ is given to point $A$ and point $B$ is earthed, what is the potential at the point $P$….$V$

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