In figure a potential of + 1200, V is given to point A and point B is earthed, potential at point P

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1. Electric Charges and Fields

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In the figure a potential of $+ 1200\, V$ is given to point $A$ and point $B$ is earthed, what is the potential at the point $P$....$V$

A

$100$

B

$200$

C

$400$

D

$600$

Solution

Given circuit can be reduced as follows

In series combination charge on each capacitor remains same. So using

$Q=C V$

$\Rightarrow C_{1} V_{1}=C_{2} V_{2} \Rightarrow 3\left(1200-V_{p}\right)=6\left(V_{p}-V_{B}\right)$

$\Rightarrow 1200-V_{p}=2 V_{p}\left(\because V_{B}=0\right)$

$\Rightarrow 3 V_{p}=1200 \Rightarrow V_{p}=400$ volt

Standard 12

Physics

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