In the figure a potential of + 1200, V is giv | vedclass

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Question

Given circuit can be reduced as follows

In series combination charge on each capacitor remains same. So using

$Q=C V$

$\Rightarrow C_{1} V_{1

Vedclass · Accepted Answer

$400$

Vedclass · Answer

Given circuit can be reduced as follows

In series combination charge on each capacitor remains same. So using

$Q=C V$

$\Rightarrow C_{1} V_{1}=C_{2} V_{2} \Rightarrow 3\left(1200-V_{p}\right)=6\left(V_{p}-V_{B}\right)$

$\Rightarrow 1200-V_{p}=2 V_{p}\left(\because V_{B}=0\right)$

$\Rightarrow 3 V_{p}=1200 \Rightarrow V_{p}=400$ volt

In the figure a potential of $+ 1200\, V$ is given to point $A$ and point $B$ is earthed, what is the potential at the point $P$....$V$

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