The following table show os the positon of three persons between $8.00\, am$ to $8.20\, am$.

Time Position (in $km$)  
Person $A$ Person $B$ Person $C$
$8.00 \,am$ $0$ $0$ $0$
$8.05 \,am$ $4$ $5$ $10$
$8.10\, am$ $13$ $10$ $19$
$8.15 \,am$ $20$ $15$ $24$
$8.20\, am$ $25$ $20$ $27$

 $(i)$ Who is moving with constant speed ?

$(ii)$ Who has travelled maximum distance between $8.00\, am$ to $8.05\, am$ ?

$(iii)$ Calculate the average speed of person $'A^{\prime}$ in $k m h^{-1}$

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$(i)$ Person $B$ is moving with constant speed as he travels equal distance $(5 km )$ in equal intervals of time, i.e., in every $5$ minutes.

$(ii)$ Person $C$. He travelled $10 km$.

$(iii)$ Average speed of person"

$A=\frac{\text { Total distance travelled by } A}{\text { Total time taken }}$

$=\frac{25 km }{20 min }=\frac{25 \times 60}{20} km h ^{-1}$

$=75 km h ^{-1}$

Similar Questions

An object is moving along a straight line with uniform acceleration. The following table gives the velocity of the object at various instants of time

Time $(s)$ $0$ $1$ $2$ $3$ $4$ $5$ $6$
Velocity $\left( m s ^{-1}\right)$ $2$ $4$ $6$ $8$ $10$ $12$ $14$

Plot the graph.

From the graph.

$(i)$ Find the velocity of the object at the end of $2.5 sec$

$(ii)$ Calculate the acceleration.

$(iii)$ Calculate' the distance covered in the last $4$ sec.

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$(i)$ Find the speed of the object during first four seconds of its journey.

$(ii)$ How long was it stationary ?

$(iii)$ Does it represent a real situation ? Justify your answer.

Name a physical quantity that essentially changes as a body moves.

A body is thrown vertically upward with velocity $u$, the greatest height $h$ to which it will rise is,

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