The force acting on the block pushes it, then | vedclass

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Question

$\mathrm{N}=\mathrm{mg}+\mathrm{F} \cos 	heta=\operatorname{mg}(1+\cos 	heta)=2 \mathrm{mg} \cos ^{2} \frac{	heta}{2}$
Pushing of the block will b

Vedclass · Accepted Answer

$	an \,\frac{	heta }{2} \ge \mu $

Vedclass · Answer

$\mathrm{N}=\mathrm{mg}+\mathrm{F} \cos 	heta=\operatorname{mg}(1+\cos 	heta)=2 \mathrm{mg} \cos ^{2} \frac{	heta}{2}$
Pushing of the block will be possible if
$F \sin 	heta \geq \mu N$
$\Rightarrow \operatorname{mg}\left(2 \sin \frac{	heta}{2} \cos \frac{	heta}{2}ight) \geq \mu\left(2 \operatorname{mg} \cos ^{2} \frac{	heta}{2}ight)$
$\Rightarrow 	an \frac{	heta}{2} \geq \mu$

The force acting on the block pushes it, then pushing of the block will be possible along the surface if

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