The force-deformation equation for a nonlinear spring fixed at one end is $F =4x^{1/ 2}$ , where $F$ is the force (expressed in newtons) applied at the other end and $x$ is the deformation expressed in meters
The force-deformation equation for a nonlinear spring fixed at one end is $F =4x^{1/ 2}$ , where $F$ is the force (expressed in newtons) applied at the other end and $x$ is the deformation expressed in meters
- A
This spring mass system execute $SHM$ .
- B
The deformation $x_0$ if a $100\ g$ block is suspended from the spring and is at rest is $0.625\ m$ .
- C
Assuming that the slope of the force deformation curve at the point corresponding to the deformation $x_0$ can be used as an equivalent spring constant, then the frequency of vibration of the block is $\frac{{4\sqrt 5 }}{{2\pi }}$ .
- D
None of these
Similar Questions
Consider two identical springs each of spring constant $k$ and negligible mass compared to the mass $M$ as shown. Fig. $1$ shows one of them and Fig. $2$ shows their series combination. The ratios of time period of oscillation of the two $SHM$ is $\frac{ T _{ b }}{ T _{ a }}=\sqrt{ x },$ where value of $x$ is
(Round off to the Nearest Integer)
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(Round off to the Nearest Integer)
- [JEE MAIN 2021]
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- [JEE MAIN 2021]