The force on a hemisphere of radius 1, cm if | vedclass

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Question

$\mathrm{p}=\frac{\mathrm{h}}{\lambda}$ of each photon

$=\frac{6.63 	imes 10^{-34}}{500 	imes 10^{-9}}=1.33 	imes 10^{-27} \mathrm{\,kg}-\mathrm

Vedclass · Accepted Answer

$5.22	imes10^{-9}\, N$

Vedclass · Answer

$\mathrm{p}=\frac{\mathrm{h}}{\lambda}$ of each photon

$=\frac{6.63 	imes 10^{-34}}{500 	imes 10^{-9}}=1.33 	imes 10^{-27} \mathrm{\,kg}-\mathrm{m} / \mathrm{s}$

and no. of photons

$=\frac{0.5}{\mathrm{hv}} / \mathrm{cm}^{2}=\frac{0.5 \lambda}{\mathrm{hc}} / \mathrm{cm}^{2}$

$=\frac{0.5 	imes 500}{1240 	imes 1.6 	imes 10^{-19}} / \mathrm{cm}^{2}$

$=1.25 	imes 10^{18}$ $\mathrm{photons}$ $/ \mathrm{cm}^{2}$

$	herefore$ force $=1.25 	imes 10^{8} 	imes 1.33 	imes 10^{-27} 	imes \pi 	imes 1^{2}$

$=5.22 	imes 10^{-9} \mathrm{\,N}$

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