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8.Mechanical Properties of Solids
easy
The force required to stretch a wire of crosssection $1 cm ^{2}$ to double its length will be ........ $ \times 10^{7}\,N$
(Given Yong's modulus of the wire $=2 \times 10^{11}\,N / m ^{2}$ )
A
$1$
B
$1.5$
C
$2$
D
$2.5$
(JEE MAIN-2022)
Solution
$F =Y A \frac{\Delta l}{l}$
$=2 \times 10^{11} \times 10^{-4}\left(\frac{2 l-l}{l}\right)$
$=2 \times 10^{7}\,N$
Standard 11
Physics