Gujarati
Hindi
14.Waves and Sound
hard

The fundamental frequency of a sonometer wire increases by $6$ $Hz$ if its tension is increased by $44\%$ keeping the length constant. The change in the fundamental frequency of the sonometer wire in $Hz$ when the length of the wire is increased by $20\%$, keeping the original tension in the wire will be :-

A

$2$

B

$4$

C

$5$

D

$10$

Solution

Fundamental frequency of sonometer

${\rm{n}} = \frac{1}{{2l}}\sqrt {\frac{{\rm{T}}}{{\rm{m}}}} $

when tension is increased by $44 \%$ then $n^{\prime}=n+6$

$ \Rightarrow {\rm{n}} + 6 = \frac{1}{{2l}}\sqrt {\frac{{1.44{\rm{T}}}}{{\rm{m}}}}  = 1.2{\rm{n}} \Rightarrow {\rm{n}} = 30\,{\rm{Hz}}$

When length of the wire is increased by $20 \%$ then

${{\rm{n}}^\prime } = \frac{1}{{2{l^\prime }}}\sqrt {\frac{{\rm{T}}}{{\rm{m}}}}  = \frac{1}{{2(1.2l)}}\sqrt {\frac{{\rm{T}}}{{\rm{m}}}}  = \left( {\frac{1}{{1.2}}} \right)(30) = 25\,{\rm{Hz}}$

Change in frequency $=30-25=5 \mathrm{\,Hz}$

Standard 11
Physics

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