14.Waves and Sound
medium

The string of a violin has a frequency of $440 \,cps$. If the violin string is shortened by one fifth, its frequency will be changed to ........... $cps$

A

$440$

B

$880$

C

$550$

D

$2200$

Solution

(d)

Fundamental frequency $=440 \,cps =\frac{v}{2 l}$

If $l$ is made one fifth $\frac{v}{2 \times l / 5}$ or $\frac{5 v}{2 l}$

Since $\frac{v}{2 l}=440$

$5 \frac{v}{2 l}=5 \times 440=2200$

Standard 11
Physics

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