Trigonometrical Equations
normal

The general solution of $sin\, x + sin \,5x = sin\, 2x + sin \,4x$ is :

A

$2n\pi$

B

$n\pi$

C

$n\pi /3$

D

$2 n\pi /3$ where $n \in I$

Solution

$sinx + sin5x = sin2x + sin4x$

$2 \,sin3x \, cos2x = 2\, sin3x \,cosx$

$2sin3x [ cos2x – cosx] = 0$

On solving we get $x = n\pi /3$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.