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Trigonometrical Equations
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$sin\, x + sin \,5x = sin\, 2x + sin \,4x$ ના વ્યાપક ઉકેલ ......... થાય
A
$2n\pi$
B
$n\pi$
C
$n\pi /3$
D
$2 n\pi /3$ જ્યાં $n \in I$
Solution
$sinx + sin5x = sin2x + sin4x$
$2 \,sin3x \, cos2x = 2\, sin3x \,cosx$
$2sin3x [ cos2x – cosx] = 0$
On solving we get $x = n\pi /3$
Standard 11
Mathematics