Gujarati
5.Work, Energy, Power and Collision
easy

The graph between $\sqrt E $and $\frac{1}{p}$ is ($E$=kinetic energy and $p = $ momentum)

A
B
C
D

Solution

(c)$P = \sqrt {2mE} $ it is clear that $P \propto \sqrt E $
So the graph between $P$ and $\sqrt E $ will be straight line.
but graph between $\frac{1}{P}$ and $\sqrt E $ will be hyperbola

Standard 11
Physics

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