The graph given below is the distance$-$time graph of an object.

$(i)$ Find the speed of the object during first four seconds of its journey.

$(ii)$ How long was it stationary ?

$(iii)$ Does it represent a real life situation ? Justify your answer.

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$(i)$ $\frac{(75-0)}{(4-0)}=\frac{75}{4}=18.75 m s ^{-1}$

$(ii)$ $(14-4)=10 s$

$(iii)$ No as distance cannot decrease with time.

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