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12.Kinetic Theory of Gases
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The graph which represents the variation of mean kinetic energy of molecules with temperature $t^o\ C $ is
A

B

C

D

Solution
Mean kinetic energy of gas moleules
$E=\frac{f}{2} k T=\frac{f}{2} k(t+273)=\left(\frac{f}{2} k\right) t+\frac{f}{2} \times 273 k$
Comparing it with standard equationof staright line $\mathrm{y}=\mathrm{mx}+\mathrm{c} .$ We get $\mathrm{m}=\mathrm{f} / 2 \mathrm{k}$ and $c=f / 273 \mathrm{k} .$ So the graph between $\mathrm{E}$ and $\mathrm{t}$ will be straight line with positive intercept on E-axis and positive slope with $t-axis$
Standard 11
Physics
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