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13.Nuclei
easy
The half life of a radioactive element which has only $\frac{1}{{32}}$ of its original mass left after a lapse of $60\, days$ is ........$days$
A
$12$
B
$32$
C
$60$
D
$64$
Solution
(a) $\frac{{{N_0}}}{{32}} = {N_0}{\left( {\frac{1}{2}} \right)^{60/T}}$
$\Rightarrow 5 = \frac{{60}}{T} \Rightarrow T = 12\, days$
Standard 12
Physics