Gujarati
13.Nuclei
easy

The half life of a radioactive element which has only $\frac{1}{{32}}$ of its original mass left after a lapse of $60\, days$ is ........$days$

A

$12$

B

$32$

C

$60$

D

$64$

Solution

(a) $\frac{{{N_0}}}{{32}} = {N_0}{\left( {\frac{1}{2}} \right)^{60/T}}$

$\Rightarrow 5 = \frac{{60}}{T} \Rightarrow T = 12\, days$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.