The height $y$ and the distance $x$ along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = (8t - 5{t^2})$ meter and $x = 6t\, meter$, where $t$ is in second. the angle with the horizontal at which the projectile was projected is

  • A

    ${\tan ^{ - 1}}(3/4$)

  • B

    ${\tan ^{ - 1}}(4/3)$

  • C

    ${\sin ^{ - 1}}(3/4$)

  • D

    Not obtainable from the given data

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