The height $y$ and the distance $x$ along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by $y = (8t - 5{t^2})$ meter and $x = 6t\, meter$, where $t$ is in second. the angle with the horizontal at which the projectile was projected is
${\tan ^{ - 1}}(3/4$)
${\tan ^{ - 1}}(4/3)$
${\sin ^{ - 1}}(3/4$)
Not obtainable from the given data
Two projectiles are thrown simultaneously in the same plane from the same point. If their velocities are $v_1$ and $v_2$ at angles $\theta _1$ and $\theta_2$ respectively from the horizontal, then answer the following question
The trajectory of particle $1$ with respect to particle $2$ will be
A particle has initial velocity $\left( {2\hat i + 3\hat j} \right)$ and acceleration $\left( {0.3\hat i + 0.2\hat j} \right)$. The magnitude of velocity after $10\, seconds$ will be
Velocity of a particle moving in a curvilinear path in a horizontal $X$ $Y$ plane varies with time as $\vec v = (2t\hat i + t^2 \hat j) \ \ m/s.$ Here, $t$ is in second. At $t = 1\ s$
A point moves in $x -y$ plane according to the law $x = 3\, cos\,4t$ and $y = 3\, (1 -sin\,4t)$. The distance travelled by the particle in $2\, sec$ is...........$m$ (where $x$ and $y$ are in $metres$ )
What can be the angle between velocity and acceleration for the motion on a straight line ? Explain with example.