The incorrect statement regarding $'X'$ in given reaction is $B{F_3} + LiAl{H_4}\xrightarrow{{Ether}}\left( X \right) + LiF + Al{F_3}$

Given below are the statements about diborane.

$(a)$ Diborane is prepared by the oxidation of $\mathrm{NaBH}_{4}$ with $\mathrm{I}_{2}$.

$(b)$ Each boron atom is in sp $^{2}$ hybridized state.

$(c)$ Diborane has one bridged $3$ centre$-2-$electron bond.

$(d)$ Diborane is a planar molecule.

The option with correct statement(s) is :

Write balanced equations for:

$(i)$ $BF _{3}+ LiH \rightarrow$

$(ii)$ $B _{2} H _{6}+ H _{2} O \rightarrow$

$(\text { iii }) NaH + B _{2} H _{6} \rightarrow$

$(i v) H_{3} B O_{3} \stackrel{\Delta}{\longrightarrow}$

$( v ) Al + NaOH \rightarrow$

$( v i ) B _{2} H _{6}+ NH _{3} \rightarrow$

Correct match is :

Identify the reaction which does not liberate hydrogen

Complete the following chemical equations :

$Z + 3LiAl{H_4} \to X + 3LiF + 3Al{F_3}$

$X + 6{H_2}O \to Y + 6{H_2}$

$3X + 3{O_2}\xrightarrow{\Delta }{B_2}{O_3} + 3{H_2}O$