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p-Block Elements - I
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The incorrect statement regarding $'X'$ in given reaction is $B{F_3} + LiAl{H_4}\xrightarrow{{Ether}}\left( X \right) + LiF + Al{F_3}$
A
Twelve electrons are involved in bonding
B
Four, two centre-two electron bonds
C
Two, three centre-two electron bonds
D
$X$ does not react with $NH_3$
Solution
$B{F_3} + LiAl{H_4}\xrightarrow{{Ether}}\mathop {{B_2}{H_6}}\limits_{(x)} + LiF + Al{F_3}$
$NH_3$ can react with $B_2H_6,$
${B_2}{H_6} + 2N{H_3}\xrightarrow{{warm}}{[B{H_2}.2N{H_3}]^ + }.{[B{H_4}]^ – }$ $\xrightarrow{{200{\,^o}C}}{B_3}{N_3}{H_6}$ (Inorganic benzene)
Standard 11
Chemistry
