The incorrect statement regarding molecular orbital $(s)$ is
If there is a nodal plane perpendicular to the internuclear axis and lying between the nuclei of bonded atoms then corresponding orbitals is antibonding $M.O.$
If a nodal plane lies in the inter-nuclear axis, then corresponding orbitals is $pi(\pi)$ bonding $M .O.$
The $\sigma$ -bonding molecular orbital does not contain nodal planes containing the ternuclear axis
The $\delta$ -bonding molecular orbital possesses three nodal planes containing the internuclear axis.
During the change of $O_2$ to $O_2^-$, the incoming electron goes to the orbital
Compare the relative stability of the following species and indicate their magnetic properties;
$O _{2}, O _{2}^{+}, O _{2}^{-}$ (superoxide), $O _{2}^{2-}$ (peroxide)
If the magnetic moment of a dioxygen species is $1.73 \;B.M$, it may be
The correct statement$(s)$ about $O _3$ is (are)
$(A)$ $O$ - $O$ bond lengths are equal.
$(B)$ Thermal decomposition of $O _3$ is endothermic.
$(C)$ $O _3$ is diamagnetic in nature.
$(D)$ $O _3$ has a bent structure.
Stability of the species $Li_2, Li_2^-$ and $Li_2^+$ increases in the order of :