The incorrect statement regarding molecular orbital $(s)$ is
The incorrect statement regarding molecular orbital $(s)$ is
- A
If there is a nodal plane perpendicular to the internuclear axis and lying between the nuclei of bonded atoms then corresponding orbitals is antibonding $M.O.$
- B
If a nodal plane lies in the inter-nuclear axis, then corresponding orbitals is $pi(\pi)$ bonding $M .O.$
- C
The $\sigma$ -bonding molecular orbital does not contain nodal planes containing the ternuclear axis
- D
The $\delta$ -bonding molecular orbital possesses three nodal planes containing the internuclear axis.
Similar Questions
Which of the following statement is not correct?
Which of the following statement is not correct?
Which of the following is diamagnetic
Which of the following is diamagnetic
What is bond order according to Lewis ? Write structure and bond order of ${{\rm{H}}_2}{\rm{,}}{{\rm{O}}_2},{{\rm{N}}_2},{\rm{CO}},{\rm{NO}}$.
What is bond order according to Lewis ? Write structure and bond order of ${{\rm{H}}_2}{\rm{,}}{{\rm{O}}_2},{{\rm{N}}_2},{\rm{CO}},{\rm{NO}}$.
According to molecular orbital theory, the number of unpaired electron(s) in $\mathrm{O}_{2}^{2-}$ is :
According to molecular orbital theory, the number of unpaired electron(s) in $\mathrm{O}_{2}^{2-}$ is :
- [JEE MAIN 2021]
From elementary molecular orbital theory we can give the electronic configuration of the singly positive nitrogen molecular ion $N_2^ + $ as
From elementary molecular orbital theory we can give the electronic configuration of the singly positive nitrogen molecular ion $N_2^ + $ as