Initial activity of a certain radioactive isotope was measured as 16000 counts min^{-1} . Give

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13.Nuclei

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The initial activity of a certain radioactive isotope was measured as $16000\ counts\ min^{-1}$. Given that the only activity measured was due to this isotope and that its activity after $12\, h$ was $2000\ counts\ min^{-1}$, its half-life, in hours, is nearest to

A

$9$

B

$6$

C

$4$

D

$3$

Solution

$A=A_{0} e^{-\lambda t}$

$2000=16000 \mathrm{e}^{-12 x}$

$\mathrm{T}=\frac{0.693 \times 6}{1}=4$

Standard 12

Physics

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