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3-2.Motion in Plane
medium
The initial position of an object at rest is given by $3 \hat{i}-8 \hat{j}$ It moves with constant acceleration and reaches to the position $2 \hat{i}+4 \hat{j}$ after $4 \,s$. What is its acceleration?
A
$-\frac{1}{8} \hat{i}+\frac{3}{2} \hat{j}$
B
$2 \hat{i}-\frac{1}{8} \hat{j}$
C
$-\frac{1}{2} \hat{i}+8 \hat{j}$
D
$8 \hat{i}-\frac{3}{2} \hat{j}$
Solution
(a)
initial position $\quad x_i=3 \quad y_i=-8$
final position $\quad x_t=2 \quad y_f=4$
$x_f-x_i=\frac{1}{2} a_x t^2=-1$
$y_f-y_i=\frac{1}{2} a_y t^2=12$
$a_x=-\frac{2}{16}=-\frac{1}{8}$
$a y=\frac{24}{16}=\frac{3}{2}$
$a=-\frac{1}{8} \hat{\imath}+\frac{3}{2} \hat{\jmath}=\text { option (A) }$
Standard 11
Physics
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