The ionisation constant of acetic acid is 1.8 | vedclass

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Question

When acetic acid is dissolved in water, it partially dissociates ( $2 \,\%)$. Ionisation constant $K _{ a }=1.87 	imes 10^{-5}$

$K _{ a }=\frac{ C

Vedclass · Accepted Answer

$0.045$

Vedclass · Answer

When acetic acid is dissolved in water, it partially dissociates ( $2 \,\%)$. Ionisation constant $K _{ a }=1.87 	imes 10^{-5}$

$K _{ a }=\frac{ C \alpha 	imes C \alpha}{ C (1-\alpha)}$

We assume $\alpha \sim 0 \Rightarrow 1-\alpha \sim 1$

$\Rightarrow 1.8 	imes 10^{-5}=\frac{ Ca ^2}{1}= C 	imes 0.02 	imes 0.02$

$\Rightarrow C =\frac{1.8 	imes 10^{-5}}{0.02^2}$

$=0.045 \,M$

The ionisation constant of acetic acid is $1.8 \times 10^{-5}$. The concentration at which it will be dissociated to $2\%$, is

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