The latus rectum of the hyperbola $9{x^2} - 16{y^2} - 18x - 32y - 151 = 0$ is
The latus rectum of the hyperbola $9{x^2} - 16{y^2} - 18x - 32y - 151 = 0$ is
- A
$\frac{9}{4}$
- B
$9$
- C
$\frac{3}{2}$
- D
$\frac{9}{2}$
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