Left end of a massless stick with length l is placed on corner of a table, as shown in Fig. A point

English

Gujarati

Hindi

6.System of Particles and Rotational Motion

medium

The left end of a massless stick with length $l$ is placed on the corner of a table, as shown in Fig. A point mass $m$ is attached to the center of the stick, which is initially held horizontal. It is then released. Immediately afterward, what normal force does the table exert on the stick?

A

$0$

B

$mg/6$

C

$mg/2$

D

$mg$

Solution

$m g-N_{Y}=ma$ $…(i)$

$\operatorname{mg} \frac{\ell}{2}=\left[\mathrm{m}\left(\frac{\ell}{2}\right)^{2}\right] \alpha$ $…(ii)$

$\mathrm{N}_{\mathrm{Y}}=0$

Standard 11

Physics

Share

Similar Questions

A rod of mass $1\ kg$ , length $1\ m$ is suspended horizontally with the help of two ideal strings as shown in figure. First a mass is suspended to the left most end keeping rod horizontal, than a second mass is suspended to the right most end again keeping horizontal orientation. The maximum total mass that can be suspended in that way keeping horizontal orientation of rod ……. $kg.$

medium

$A$ man can move on a horizontal plank supported symmetrically as shown. The variation of normal reaction on support $A$ with distance $x$ of the man from the end of the plank is best represented by :

hard

A massless string is wrapped round a disc of mass $M$ and radius $R$. Another end is tied to a mass $m$ which is initially at height $h$ from ground level as shown in the fig. If the mass is released then its velocity while touching the ground level will be

hard

For a system to be in equilibrium, the torques acting on it must balance. This is true only if the torques are taken about

easy

A mass $M= 40\ kg$ is fixed at the very edge of a long plank of mass $80\ kg$ and length $1\ m$ which is pivoted such that it is in equilibrium. How far (approx.) from the pivot should a mass of $100\ kg$ be attached so that the plank starts rotating with an angular acceleration of $1\ rad/s^2$?

hard