The length of a metallic rod is $5m$ at $0°C$ and becomes $ 5.01\, m$, on heating upto $100°C$. The linear expansion of the metal will be
$2.33 \times 10^{-5} {°C^{-1}}$
$6.0 \times 10^{-5} {°C^{-1}}$
$4.0 \times 10^{-5} {°C^{-1}}$
$2.0 \times 10^{-5}{°C^{-1}}$
A copper rod of length $l_1$ and an iron rod of length $l_2$ are always maintained at the same common temperature $T$. If the difference $(l_2 -l_1)$ is $15\,cm$ and is independent of the value of $T,$ the $l_1$ and $l_2$ have the values (given the linear coefficient of expansion for copper and iron are $2.0 \times 10^{-6}\,C^{-1}$ and $1.0\times10^{-6}\,C^{ -1}$ respectively)
If the length of the pendulum in pendulum clock increases by $0.1\, \%$, then the error in time per day is: (in $s$)
We would like to prepare a scale whose length does not change with temperature. It is proposed to prepare a unit scale of this type whose length remains, say $10\, cm$ We can use a bimetallic strip made of brass and iron each of different length whose length (both components) would change in such a way that difference between their lengths remain constant. If ${\alpha _{iron}}$ $= 1.2 \times 10^{-5}\,K^{-1}$ and ${\alpha _{brass}}$ $= 1.8 \times 10^{-5}\,K^{-1}$ what should we take as length of each strip ?
The volume of the bulb of a mercury thermometer at $0^o C$ is $V_0$and cross section of the capillary is $A_0$. The coefficient of linear expansion of glass is $a_g$ $per ^o C$ and the cubical expansion of mercury $\gamma_m$ $per ^o C$. If the mercury just fills the bulb at $0^o C$, what is the length of mercury column in capillary at $T^o C.$
Give name of substance that contracts with increase in temperature.