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10-1.Thermometry, Thermal Expansion and Calorimetry
easy
The length of a metallic rod is $5m$ at $0°C$ and becomes $ 5.01\, m$, on heating upto $100°C$. The linear expansion of the metal will be
A
$2.33 \times 10^{-5} {°C^{-1}}$
B
$6.0 \times 10^{-5} {°C^{-1}}$
C
$4.0 \times 10^{-5} {°C^{-1}}$
D
$2.0 \times 10^{-5}{°C^{-1}}$
Solution
(d) $\alpha = \frac{{\Delta L}}{{{L_0} \times \Delta \theta }} = \frac{{0.01}}{{5 \times 100}} = 2 \times {10^{ – 5}}{°C^{-1}}$
Standard 11
Physics
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