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10-1.Circle and System of Circles
medium
The length of the tangent from the point $(4, 5)$ to the circle ${x^2} + {y^2} + 2x - 6y = 6$ is
A
$\sqrt {13} $
B
$\sqrt {38} $
C
$2\sqrt 2 $
D
$2\sqrt {13} $
Solution
(a) Length of the tangent
$ = \sqrt {{4^2} + {5^2} + 2 \cdot 1 \cdot 4 + 2\,( – 3) \cdot 5 – 6} $
$= \sqrt {13} $.
Standard 11
Mathematics