Gujarati
10-1.Circle and System of Circles
medium

The length of the tangent from the point $(4, 5)$ to the circle ${x^2} + {y^2} + 2x - 6y = 6$ is

A

$\sqrt {13} $

B

$\sqrt {38} $

C

$2\sqrt 2 $

D

$2\sqrt {13} $

Solution

(a) Length of the tangent

$ = \sqrt {{4^2} + {5^2} + 2 \cdot 1 \cdot 4 + 2\,( – 3) \cdot 5 – 6} $

$= \sqrt {13} $.

Standard 11
Mathematics

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