Locus of point of instruction of lines √ 3 x - y - 4 √ 3 t = 0 & √ 3tx + ty

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10-2. Parabola, Ellipse, Hyperbola

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The locus of the point of instruction of the lines $\sqrt 3 x - y - 4 \sqrt 3 t = 0$ $\&$ $\sqrt 3tx + ty - 4\sqrt 3 = 0$ (where $ t$ is a parameter) is a hyperbola whose eccentricity is

A

$\sqrt 3$

B

$2$

C

$\frac{2}{{\sqrt 3 }}$

D

$\frac{4}{3}$

Solution

hyperbola $\frac{{{x^2}}}{{16}} – \frac{{{y^2}}}{{48}} = 1$

Standard 11

Mathematics

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