The magnetic field of earth at the equator is | vedclass

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Question

Given, $B=4 	imes 10^{-5} \,\mathrm{T}$

$\mathrm{R}_{\mathrm{E}}=6.4 	imes 10^{6}\, \mathrm{m}$

Dipole moment of the earth $\mathrm{M}=?$

$

Vedclass · Accepted Answer

${10^{23}}\,A\,{m^2}$

Vedclass · Answer

Given, $B=4 	imes 10^{-5} \,\mathrm{T}$

$\mathrm{R}_{\mathrm{E}}=6.4 	imes 10^{6}\, \mathrm{m}$

Dipole moment of the earth $\mathrm{M}=?$

$B = \frac{{{\mu _0}M}}{{4\pi {d^3}}}$

$4 	imes {10^{ - 5}} = \frac{{4\pi  	imes {{10}^{ - 7}} 	imes {	ext{M}}}}{{4\pi  	imes \left( {6.4 	imes {{10}^6}} ight.{)^3}}}$

$\mathrm{M} \cong 10^{23}\, \mathrm{Am}^{2}$

The magnetic field of earth at the equator is approximately $4 \times 10^{-5}\, T$ . The radius of earth is $6.4 \times 10^6\, m$. Then the dipole moment of the earth will be nearly of the order of

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