The magnetic field to a small magnetic dipole of magnetic moment $M$, at distance $ r$ from the centre on the equatorial line is given by (in $M.K.S. $ system)
$\frac{{{\mu _0}}}{{4\pi }} \times \frac{M}{{{r^2}}}$
$\frac{{{\mu _0}}}{{4\pi }} \times \frac{M}{{{r^3}}}$
$\frac{{{\mu _0}}}{{4\pi }} \times \frac{{2M}}{{{r^2}}}$
$\frac{{{\mu _0}}}{{4\pi }} \times \frac{{2M}}{{{r^3}}}$
A small current element of length $d \ell$ and carrying current is placed at $(1,1,0)$ and is carrying current in ' $+ z$ ' direction. If magnetic field at origin be $\overrightarrow{ B }_1$ and at point $(2,2,0)$ be $\overrightarrow{ B }_2$ then
Three identical bar magnets each of magnetic moment $M$ are placed in the form of an equilateral triangle as shown. The net magnetic moment of the system is
Two points $A$ and $B$ are situated at a distance $x$ and $2x$ respectively from the nearer pole of a magnet $2\,cm$ long. The ratio of magnetic field at $A$ and $B$ is
Two short bar magnets of magnetic moments ' $M$ ' each are arranged at the opposite corners of a square of side ' $d$ ', such that their centres coincide with the corners and their axes are parallel to one side of the square. If the like poles are in the same direction, the magnetic induction at any of the other corners of the square is
Due to a small magnet, intensity at a distance $x$ in the end on position is $9$ $gauss$ . What will be the intensity at a distance $\frac{x}{2}$ on broad side on position....$gauss$