Magnetic needle of a tangent galvanometer is deflected at an angle 30^o due to a magnet. horizontal

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5.Magnetism and Matter

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The magnetic needle of a tangent galvanometer is deflected at an angle $30^o$ due to a magnet. The horizontal component of the earth's magnetic field is $0.34 \times 10^{-4}\, T$ which is along the plane of the coil. The magnetic field due to magnet is

A

$1.96 \times {10^{ - 4}}\,T$

B

$1.96 \times {10^{ - 5}}\,T$

C

$1.96 \times {10^{ 4}}\,T$

D

$1.96 \times {10^{ 5}}\,T$

Solution

$B=0.34 \times 10^{-4} T$

Deflected angle $\theta =30^{\circ}$

So magnetic intensity is $B \tan 30^{\circ}$

$=0.34 \times 10^{-4} T \times \frac{1}{\sqrt{3}}$

$=1.96 \times 10^{-5} T$

Where, $\tan 30^{\circ}=\frac{1}{\sqrt{3}},$ and $\sqrt{3}=1.73 \mathrm{c}$

Standard 12

Physics

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