Time period of a vibration magnetometer is T_0 . Its magnet is replaced by another magnet whose mome

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5.Magnetism and Matter

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The time period of a vibration magnetometer is $T_0$. Its magnet is replaced by another magnet whose moment of inertia is $3$ times and magnetic moment is $1/3$ of the initial magnet. The time period now will be

A

$3T_0$

B

$T_0$

C

$T_0 /\sqrt 3$

D

$T_0/3$

Solution

The time period of oscillation is given by

$T_{0}=2 \pi \sqrt{\frac{I_{0}}{M B}}$

$I_{1}=3 I_{0}$

$M_{1}=\frac{M_{0}}{3}$

$\frac{T_{1}}{T_{0}}=\sqrt{\frac{I_{1} M_{0}}{I_{0} M_{1}}}$

$T_{1}=3 T_{0}$

Standard 12

Physics

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