Masses of 10, kg and 20 ,kg respectively are connected by a massless spring as shown in figure. A fo

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4-1.Newton's Laws of Motion

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The masses of $10\, kg$ and $20 \,kg$ respectively are connected by a massless spring as shown in figure. A force of $200\, N$ acts on the $20\, kg$ mass. At the instant shown, the $10\, kg$ mass has acceleration $12\,m/{\sec ^2}$. What is the acceleration of $20\, kg$ mass ........... $m/{\sec ^2}$

A

$12$

B

$4$

C

$10$

D

$0$

Solution

(b) As the mass of $10\, kg$ has acceleration $12\, m/s^2$ therefore it apply $120N$ force on mass $20\,kg$ in a backward direction.

$\therefore $ Net forward force on $20\, kg$ mass $= 200 -120 = 80N$

$\therefore $ Acceleration $ = \frac{{80}}{{20}} = 4\,m/{s^2}$.

Standard 11

Physics

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