Maximum possible acceleration of a train moving on a straight track is 10 m/s^2 and

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2.Motion in Straight Line

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The maximum possible acceleration of a train moving on a straight track is $10\ m/s^2$ and maximum possible retardation is $5 \ m/s^2.$ If maximum achievable speed of train is $10\ m/s$ then minimum time in which train can complete a journey of $135\ m$ starting from rest and ending at rest, is.........$s$

A

$5$

B

$10$

C

$15$

D

$20$

Solution

$\frac{1}{2}(1+2)(10)+10 t=135$

$t=12 s$

Standard 11

Physics

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