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6-2.Equilibrium-II (Ionic Equilibrium)
medium
The molar solubility $(mol\;{L^{ - 1}})$ of a sparingly soluble salt $M{X_4}$ is $'s'$. The corresponding solubility product is ${K_{sp}}$. $'s'$ is given in terms of $_{{K_{sp}}}$ by the relation
A
$s = {(256{K_{sp}})^{1/5}}$
B
$s = {(128{K_{sp}})^{1/4}}$
C
$s = {({K_{sp}}/128)^{1/4}}$
D
$s = {({K_{sp}}/256)^{1/5}}$
(AIEEE-2004)
Solution
(d) $M{X_4} \to \mathop M\limits_s + \mathop {4X}\limits_{4s} $ ;
${K_{sp}} = {(4s)^4}s$; ${K_{sp}} = 256{s^5}$
$s = {\left( {\frac{{{K_{sp}}}}{{256}}} \right)^{1/5}}$
Standard 11
Chemistry