Solubility product of 1 × {10^{ - 5}} is 1.44 × {10^{ - 4}} at {100,^o}C . solubility of silver ch

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6-2.Equilibrium-II (Ionic Equilibrium)

hard

The solubility product of $1 \times {10^{ - 5}}$ is $1.44 \times {10^{ - 4}}$ at ${100\,^o}C$. The solubility of silver chloride in boiling water may be

A

$0.72 \times {10^{ - 4}}\,M$

B

$1.20 \times {10^{ - 2}}\,M$

C

${80\,^o}C$

D

$0.5\,M\,HCOOH,$

Solution

(b) $AgCl \rightleftharpoons [A{g^ + }]\,\,[C{l^ – }]$

;${K_{sp}} = S \times S$ ; ${K_{sp}} = {S^2}$

$S = \sqrt {{K_{sp}}} $$ = \sqrt {1.44 \times {{10}^{ – 4}}} $ $ = 1.20 \times {10^{ – 2}}$ $M$.

Standard 11

Chemistry

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