Moles of Ag^+ which must be added to decrease concentration of Cl^- from 4 × 10^{-5} M to 10^{

English

Gujarati

Hindi

6-2.Equilibrium-II (Ionic Equilibrium)

hard

The moles of $Ag^+$ which must be added to decrease the concentration of $Cl^-$ from $4 × 10^{-5}$ $M$ to $10^{-5}\,M$ in $100$ $ml$ solution, if $K_{sp}$ for $AgCl$ is $10^{-10}\,M^2$ at $25\,^oC$

$4 × 10^{-5}$ $mole$

$2 × 10^{-5}$ $mole$

$3 × 10^{-6}$ $mole$

$4 × 10^{-6}$ $mole$

$\mathop {AgCl(s)}\limits_y \leftrightarrow \mathop {A{g^ + }(aq.)}\limits_{x – y} + \mathop {C{l^ – }(aq.)}\limits_{4 \times {{10}^{ – 5}} – y} $

$4 \times 10^{-5}-y=10^{-5}$

$y=3 \times 10^{-5}$

$(x-y)\left(4 \times 10^{-5}-y\right)=10^{-10}$

$(x-y)\left(10^{-3}\right)=10^{-10}$

$x-y=10^{-5}$

$x-3 \times 10^{-5}=10^{-5}$

$x=4 \times 10^{-5}$

Standard 11

Chemistry

medium

medium

medium

easy

medium